Question 378469: On this problem: A photo is 10 cm longer than it is wide. It is mounted in a frame 2 cm wide. The area of the frame is 112cm squared. Find the dimensions of the photo. \ I have no idea even where to start!
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
Let  represent the width of the photo. Then the length of the photo must be  . Since the frame is 2 cm wide, it adds 2 cm to EACH side, top, and bottom. So the overall width, including the frame, must be  cm, and the overall length must be  cm. The area of a rectangle is the length times the width:
(x\ +\ 14)\ =\ 112)
Solve the quadratic, exclude the negative root, and the positive root is the width of the photo. Note: This ugly beast does NOT factor. You need to haul out the quadratic formula. And this is one really odd shaped photo.
John
My calculator said it, I believe it, that settles it
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