SOLUTION: I need to graph the solution set of the system of inequalities or indicate that the system has no solution. There are two equations. First equation. x^2+y^2 is less than or e

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need to graph the solution set of the system of inequalities or indicate that the system has no solution. There are two equations. First equation. x^2+y^2 is less than or e      Log On


   

Question 378281: I need to graph the solution set of the system of inequalities or indicate that the system has no solution. There are two equations. First equation. x^2+y^2 is less than or equal to 81. Second equation. -5x + 5y is less than or equal to -25. How do I go about doing this?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2=81 is a circle centered at (0,0) with a radius of 9.

and
-5x%2B5y=-25
5y=5x-25
y=x-5
is a line with an x-intercept of (5,0) and a y-intercept of (0,-5).
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Solved by pluggable solver: Plot Any Inequality
Graphing function x%5E2%2By%5E2%3C=81:

graph%28+300%2C+300%2C+-12%2C+12%2C+-12%2C+12%2C+x%5E2%2By%5E2%3C=81+%29


Solved by pluggable solver: Plot Any Inequality
Graphing function -5x%2B5y%3C=-25:

graph%28+300%2C+300%2C+-12%2C+12%2C+-12%2C+12%2C+-5x%2B5y%3C=-25+%29

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The solution region is then the section contained within the circle and below the line.
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