Question 37821This question is from textbook General Mathematics
: The sum of three numbers is 66. The second number is twice the first and six less than the third. Find the numbers
This question is from textbook General Mathematics
Answer by ilana(307)   (Show Source):
You can put this solution on YOUR website! Make the numbers a, b, c.
We are given a+b+c=66, b=2a, and b=c-6.
We can solve for a and c in terms of b, so a=b/2, c=b+6.
Now, substitute a and c into the first equation, so b/2 + b + b+6 = 66, so (5/2)b=60, and b=24. Now solving for a and c gives a=b/2=12 and c=b+6=30.
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