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Question 378099:
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
x-2y=2

x=2y+2


y^2-x^2=2x+4

y^2-(2y+2)^2=2(2y+2)+4


y^2-(4y^2+8y+4)=4y+4+4


y^2-4y^2-8y-4=4y+8

y^2-4y^2-8y-4-4y-8=0

-3y^2-12y-12=0

y^2+4y+4=0

(y+2)^2=0

y+2=0

y=-2

x=2y+2=2(-2)+2=-4+2=-2

Answers: x=-2, y=-2