SOLUTION: I need to find the 6 trigonometric functions for this problem. The hypotenuse 16 an the adjacent is 12. I need the Cosine, Sine, Tangent, Secant, Cosecant, and Cotangent???

Algebra ->  Trigonometry-basics -> SOLUTION: I need to find the 6 trigonometric functions for this problem. The hypotenuse 16 an the adjacent is 12. I need the Cosine, Sine, Tangent, Secant, Cosecant, and Cotangent???       Log On


   

Question 378096: I need to find the 6 trigonometric functions for this problem. The hypotenuse 16 an the adjacent is 12. I need the Cosine, Sine, Tangent, Secant, Cosecant, and Cotangent???
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Use the Pythagorean Theorem from geometry to find the other leg of the right triangle.
(leg)^2 + (given leg)^2 = (hypotenuse)^2

(leg)^2 + (12)^2 = 16^2

(leg)^2 + 144 = 256

(leg)^2 = 256 - 144

(leg)^2 = 112

Take square root of both sides.

sqrt[(leg)^2] = sqrt[112]

leg = sqrt[112]

Let leg = x

Then x = sqrt[112].

Understand?


sinx = sqrt[112]/16

cosx = 12/16

tanx = sqrt[112]/12

cscx = 16/sqrt[112]

secx = 16/12

cotx = 12/sqrt[112]

Done!