SOLUTION: What is x/3x^2+2x-8 times (3x-4)/1?

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Question 37797This question is from textbook McDougal Little Algebra 1
: What is x/3x^2+2x-8 times (3x-4)/1? This question is from textbook McDougal Little Algebra 1

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Factor the denominator in the first term of
x/3x^2+2x-8 times (3x-4)/1 and get
x/[(3x - 4)(x + 2)] and you can see that (3x - 4) cancels out, leaving
x/(x + 2)