SOLUTION: I have two questions that I am struggling with. 1. Log x + log (x + 3)= 1 assume the log base is 10 2. log3 (2x-1)- log3 (x-4)=2 Thank you so much for your help!

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I have two questions that I am struggling with. 1. Log x + log (x + 3)= 1 assume the log base is 10 2. log3 (2x-1)- log3 (x-4)=2 Thank you so much for your help!      Log On


   

Question 377746: I have two questions that I am struggling with.
1. Log x + log (x + 3)= 1 assume the log base is 10
2. log3 (2x-1)- log3 (x-4)=2
Thank you so much for your help!
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I have two questions that I am struggling with.
1. Log x + log (x + 3)= 1 assume the log base is 10
Unless it's specified otherwise, base 10 is assumed (ln = base e, tho)
Log x + log (x + 3)= 1
log(x*(x + 3)) = log(10)
x*(x + 3) = 10
x^2 + 3x - 10 = 0
etc.
-------------
2. log3 (2x-1)- log3 (x-4)=2
log%283%2C%282x-1%29%2F%28x-4%29%29+=+log%283%2C9%29
(2x-1)/(x-4) = 9
etc.