SOLUTION: When z = -2 -2i square root 3 what is its "trigonometric form?" 2 (cos pi/6 + insi pi/6) is what I got.

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Question 377727: When z = -2 -2i square root 3 what is its "trigonometric form?"
2 (cos pi/6 + insi pi/6) is what I got.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If you mean
z+=+-2+-+i%282sqrt%283%29%29
Mag+=+sqrt%284+%2B+4%2A3%29+=+4
theta = arctan(sqrt(3)) in the 3rd Quad = 240º
--> 4 cis(240)
= 4(cos(240) + i*sin(240))
= 4(cos(4pi/3) + i*sin(4pi/3))