SOLUTION: Graph the parabolas. Show the vertex, axis of symmetry, x intercepts, y intercepts and write the domain and range in interval notation. f(x)=x^2-4x+3 f(x) = (x+1)^2-4

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Graph the parabolas. Show the vertex, axis of symmetry, x intercepts, y intercepts and write the domain and range in interval notation. f(x)=x^2-4x+3 f(x) = (x+1)^2-4      Log On


   

Question 377655: Graph the parabolas. Show the vertex, axis of symmetry, x intercepts, y intercepts and write the domain and range in interval notation.
f(x)=x^2-4x+3
f(x) = (x+1)^2-4
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Note: the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x)=x^2-4x+3 Or f(x)= (x-2)^2 -1 in vertex form: x-intercepts (3,0)&(1,0)

vertex Pt(2,-1), axis of symmetry x = 2, (0,3) the y-intercept



f(x) = (x+1)^2-4  x-intercepts (1,0)&(-3,0)

vertex Pt(-1,-4), axis of symmetry x = -1, (0,-3) the y-intercept