SOLUTION: Find the center and radius of the circle x^2+y^2-6x+2y+6=0

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Question 377632: Find the center and radius of the circle
x^2+y^2-6x+2y+6=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Find the center and radius of the circle

The standard equation of a circle with center C(h,k) and radius r is :

%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2

x^2+y^2-6x+2y+6=0

(x-3)^2 + (y+1)^2 -9 -1 + 6 = 0

(x-3)^2 + (y+1)^2 = 4

(x-3)^2 + (y+1)^2 = 2^2

Center is Pt(3,-1) r = 2