SOLUTION: can someone please check my answers to: factor the sums or differences of two cubes m^3-n^3 MY ANSWER m^3-n^3=(m-n)(m^3+mn+n^3) c^3+f^3 MY ANSWER c^3+f^3=(c+f)(c^3-cf-f^3)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: can someone please check my answers to: factor the sums or differences of two cubes m^3-n^3 MY ANSWER m^3-n^3=(m-n)(m^3+mn+n^3) c^3+f^3 MY ANSWER c^3+f^3=(c+f)(c^3-cf-f^3)      Log On


   

Question 37698This question is from textbook
: can someone please check my answers to: factor the sums or differences of two cubes
m^3-n^3
MY ANSWER m^3-n^3=(m-n)(m^3+mn+n^3)
c^3+f^3
MY ANSWER c^3+f^3=(c+f)(c^3-cf-f^3) This question is from textbook

Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
For the equation m%5E3-n%5E3
You may have made a careless mistake in your answer.
If you expand the equation you gave, the first term would be c%5E4 because you have c%5E3%2Ac.
The correct answer is:
%28m-n%29%28m%5E2%2Bmn%2Bn%5E2%29
For the second equation c%5E3%2Bf%5E3
Your answer has a tiny common error.
You also made the same error as above.
The first part is correct. %28c%2Bf%29
You should know that whenever you square a negative number, it beccomes positive.
The correct answer is:
%28c%2Bf%29%28c%5E2-cf%2Bf%5E2%29
Hope this helps!