You can put this solution on YOUR website! The "point-slope" form is:
y - y1 = m(x - x1)
.
So, given:
slope=-2/3 and passes through (-3, -5)
we plug it in to:
y - y1 = m(x - x1)
y - (-5) = (-2/3)(x - (-3))
y + 5 = (-2/3)(x + 3)
y + 5 = (-2/3)x + (-2/3)3
y + 5 = (-2/3)x - 2
y = (-2/3)x - 7 (this is what they're looking for)
The above is the "slope-intercept" form of the line
