SOLUTION: Write as a single log expression:
2(log(x)+log(x^2+1))-3log(x-2)
log(x^2)+log(x^4+1)-log(x^3-8)
log(x^2(x^4+1)-log(x^3-8)
log(x^6+x^2)-log(x^3-8)
log(x^12)-log(x^3-8)
log[(x^
Algebra ->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: Write as a single log expression:
2(log(x)+log(x^2+1))-3log(x-2)
log(x^2)+log(x^4+1)-log(x^3-8)
log(x^2(x^4+1)-log(x^3-8)
log(x^6+x^2)-log(x^3-8)
log(x^12)-log(x^3-8)
log[(x^
Log On
Question 376752: Write as a single log expression:
2(log(x)+log(x^2+1))-3log(x-2)
log(x^2)+log(x^4+1)-log(x^3-8)
log(x^2(x^4+1)-log(x^3-8)
log(x^6+x^2)-log(x^3-8)
log(x^12)-log(x^3-8)
log[(x^12)/(x^3-8)]
??? Answer by solver91311(24713) (Show Source):
The regular rules of algebra don't get suspended just because you are working with logarithms.
First use
to write:
Then use
To write:
Then use
To write:
Which satisfies the requirements of the problem. You could multiply out the two binomials, but that would be a decision based on the requirements of further calculations.
John
My calculator said it, I believe it, that settles it
