SOLUTION: Four oranges and five apples cost $2.00. Three oranges and four apples cost $1.56. Find the cost of an orange and the cost of an apple.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Four oranges and five apples cost $2.00. Three oranges and four apples cost $1.56. Find the cost of an orange and the cost of an apple.      Log On


   

Question 37656This question is from textbook
: Four oranges and five apples cost $2.00. Three oranges and four apples cost $1.56. Find the cost of an orange and the cost of an apple. This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
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4OR+5A=200 & 3OR+4A=156 IF WE MULTIPLY THE FIRST EAUATION BY 3 AND THE SECOND BY 4 WE GET
12OR+15A=600 &
12OR+16A=624 AND SUBTRACT THESE TWO WE GET
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0OR-1A=-24 OR A=24 THEN 4OR+5*24=200 OR 4OR+120=200 OR 4OR=80 OR OR=80/4 OR
OR=20 PROOF
4*20+5*24=200 OR 80+120=200 OR 200=200 & 3*20+4*24=156 OR 60+96=156 OR 156=156