You can put this solution on YOUR website! describe how to solve by factoring:
:
1. y^3 + 2y^2 - y -2
Group terms so that a common term can be factored out
(y^3 - y) + (2y^2 - 2)
Factor
y(y^2 - 1) + 2(y^2 - 1)
factor out (y^2-1), results:
(y^2 - 1)(y + 2)
;
;
2. a^4 b + ab^4
Factor out ab
ab(a^3 + b^3)
Factor as the sum of cubes:
ab(a+b)(a^2-ab+b^2)