SOLUTION: I need help. I am stuck on this one. How do I graph the following: y=(2^x+1)+3 and y=log(x)^2+1 Thank you very much

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I need help. I am stuck on this one. How do I graph the following: y=(2^x+1)+3 and y=log(x)^2+1 Thank you very much      Log On


   

Question 376401: I need help. I am stuck on this one. How do I graph the following:
y=(2^x+1)+3 and y=log(x)^2+1
Thank you very much
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Like every other graph.
Choose x values, calculate y values.
Plot x,y ordered pairs and connect them with a smooth curve.
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highlight%28y=2%5E%28x%2B1%29%2B3%29
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graph%28300%2C300%2C-10%2C10%2C-5%2C15%2C0%2C2%5E%28x%2B1%29%2B3%29
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highlight_green%28y=%28log%2810%2Cx%29%29%5E2%2B1%29
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graph%28300%2C300%2C-5%2C15%2C-5%2C5%2C0%2C%28log%2810%2Cx%29%29%5E2%2B1%29