SOLUTION: if f varies jointly as q^2 and h, and f = 54 when q = 3 and h = 2, find f when q = 4 and h = 5

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Question 376391: if f varies jointly as q^2 and h, and f = 54 when q = 3 and h = 2, find f when q = 4 and h = 5
Answer by robertb(5830) About Me  (Show Source):
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f+=+kq%5E2h, where k is a constant of proportionality. Now from the given,
54+=+k%2A3%5E2%2A2, or 54++=+18k, or k = 3, so that the working equation is f+=+3q%5E2h. When q = 4 and h = 5, f+=+3%2A4%5E2%2A5+=+240.