SOLUTION: (t^4-2t^2+4t-5)/(t^2-3) can some one walk me through this
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Question 376042
:
(t^4-2t^2+4t-5)/(t^2-3)
can some one walk me through this
Answer by
vksarvepalli(154)
(
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):
You can
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t^2-3 ] t^4-2t^2+4t-5 [ t^2+1
t^4-3t^2
--------------
t^2+4t-5
t^2+0t-3
-------------
4t-2
so,
t^4-2t^2+4t-5 = (t^2-3)(t^2+1) + (4t-2)
so (t^4-2t^2+4t-5)/(t^2-3) = (t^2+1) + (4t-2)/(t^2-3)