Question 376038: find three consecutive integers such that the sum of the second and third is forty eight more than one-fifth the smallest. Answer by amoresroy(361) (Show Source):
You can put this solution on YOUR website! find three consecutive integers such that the sum of the second and third is forty eight more than one-fifth the smallest.
Let x = the smallest integer
x+1 = the 2nd integer
x+2 = the 3rd integer
(x+1)+(x+2) = x/5 + 48
2x+3 = .2x +48
1.8x = 45
x = 25
x+1 = 26
x+2 = 27
The 3 consecutive integers are 25, 26, & 27.
