Question 375992: How man L of a 10% saline solution must be added to 40 L of a 20% saline solution to obtain a 14% saline solution? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! How many L of a 10% saline solution must be added to 40 L of a 20% saline solution to obtain a 14% saline solution?
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Let x = amount (L) of 10% saline solution
then
.10x + .20(40) = .14(x+40)
.10x + 8 = .14x + 5.6
8 = .04x + 5.6
2.4 = .04x
60 liters = x
