SOLUTION: I need to find a solution (x,y) for the following set of numbers.... y=logbase2(x+1) y=5-logbase2(x-3) I dont know how to solve this one....

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I need to find a solution (x,y) for the following set of numbers.... y=logbase2(x+1) y=5-logbase2(x-3) I dont know how to solve this one....      Log On


   

Question 375927: I need to find a solution (x,y) for the following set of numbers....
y=logbase2(x+1)
y=5-logbase2(x-3)
I dont know how to solve this one....
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Since they both equal y:
log%282%2C%28x%2B1%29%29+=+5+-+log%282%2C%28x-3%29%29
log%282%2C%28x%2B1%29%29+=+log%282%2C32%29+-+log%282%2C%28x-3%29%29
log%282%2C%28x%2B1%29%29+=+log%282%2C32%2F%28x-3%29%29
x+1 = 32/(x-3)
x%5E2+-+2x+-+3+=+32
x%5E2+-+2x+-+35+=+0
(x-7)*(x+5) = 0
x = -5 Discard, since it gives the log of a negative number
x = 7
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y+=+log%282%2C%287%2B1%29%29+=+log%282%2C8%29
y = 3
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(x,y) = (7,3)