SOLUTION: Using a calculator, determine the solutions for each question, to two decimal places, on the interval 0<=x<=2pi. sin2x = 1/sqrt2 I got one answer as 0.39 and 1.18 but how do

Algebra ->  Trigonometry-basics -> SOLUTION: Using a calculator, determine the solutions for each question, to two decimal places, on the interval 0<=x<=2pi. sin2x = 1/sqrt2 I got one answer as 0.39 and 1.18 but how do       Log On


   

Question 375922: Using a calculator, determine the solutions for each question, to two decimal places, on the interval 0<=x<=2pi.
sin2x = 1/sqrt2
I got one answer as 0.39 and 1.18 but how do I continue from there seeing as how the domain is from 0<=x<=2pi.
Thanks.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
sin%282x%29+=+1%2Fsqrt%282%29+=+sqrt%282%29%2F2
2x = pi/4 + n*2pi n = 0,1,2,3...
2x = 3pi/4 + n*2pi, n = 0,1,2,3...
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x = pi/8 + n*pi, n = 0,1,2,3...
x = pi/8, 9pi/8
x =~ 0.3926, 3.5343
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x = 3pi/8 + n*pi, n = 0,1,2,3...
x =~ 1.1781, 4.3197