SOLUTION: how to solve: log2x-log(x-7)=log3

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Question 375866: how to solve:
log2x-log(x-7)=log3


Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi





log2x-log(x-7)=log3 

log2x-log(x-7)-log3=0

log(2x/3(x-7) = 0 



10 ^0 = 2x/3(x-7)

1 = 2x/3(x-7)

3(x-7)= 2x

3x - 21 = 2x

x = 21