Question 375856: A seed company mixes two types of seed for bird feeding. One costs $1.100 per kg and the other costs $2.25 per kg. How much of each seed is needed to produce 6 kg at a cost of $8.90?
Answer by jessica43(140)   (Show Source):
You can put this solution on YOUR website! To solve this problem you need to write two separate equations using what you are given.
First, you know that there are two types of seed each priced per kg and together they must total 6 kg:
A + B = 6 (where A = is the cheaper seed, B = the more expensive seed)
This can be rewritten as A = 6 - B
Second, you know that seed A costs $1.1 per kg and seed B costs $2.25 per kg and together they equal $8.90:
1.1A + 2.25B = 8.9
Now, plug in the rewritten first equation into the second equation and solve for B:
1.1A + 2.25B = 8.9
1.1(6 - B) + 2.25B = 8.9
6.6 - 1.1B + 2.25B = 8.9
6.6 + 1.15B = 8.9
1.15B = 2.3
B = 2
So you need 2 kg of the more expensive seed (B).
Since you need 6 kg total seed, this means that you need 4 kg of the cheaper seed (A).
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