SOLUTION: Stopping an Oil Tanker: It has been shown that if an oil tanker stops its engines, then its velocity will decrease exponentially. Suppose that captin shuts off the engines when t

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Stopping an Oil Tanker: It has been shown that if an oil tanker stops its engines, then its velocity will decrease exponentially. Suppose that captin shuts off the engines when t      Log On


   



Question 375830: Stopping an Oil Tanker: It has been shown that if an oil tanker stops its engines, then its velocity will decrease exponentially. Suppose that captin shuts off the engines when the speed of the tanker is 20 mph and one minute later the speed of the tanker is 18 mph. What is the speed of the tanker after one hour?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Stopping an Oil Tanker:
It has been shown that if an oil tanker stops its engines, then its velocity will decrease exponentially.
Suppose that captain shuts off the engines when the speed of the tanker is
20 mph and one minute later the speed of the tanker is 18 mph.
What is the speed of the tanker after one hour?
:
Using the decay equation
20(2^(-1/k)) = 18
2^(-1/k) = 18%2F20
2^(-1/k) = .9
-1%2Fk = ln%28.9%29%2Fln%282%29
-1%2Fk = -.152
k = %28-1%29%2F%28-.152%29
k = 6.579:
:
Find the speed (s) of the tanker, when t = 60 min
s = 20(2^(-60/6.579))
s = 20 * .0018
s = .036 mph