SOLUTION: s^2+6s+25= solve for Solution sets
2x^2-9x=1
solve for x
Can you show me how you find the answer, not just the answer?
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-> SOLUTION: s^2+6s+25= solve for Solution sets
2x^2-9x=1
solve for x
Can you show me how you find the answer, not just the answer?
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Question 37567: s^2+6s+25= solve for Solution sets
2x^2-9x=1
solve for x
Can you show me how you find the answer, not just the answer? Answer by junior403(76) (Show Source):
You can put this solution on YOUR website! s^2+6s+25= solve for Solution sets
The s^2 indicates there will be 2 solutions.
Besure that the quadratic equation is equal to zero.
Use quadratic formula to solve.
In this case...
s^2+6s+25=0
ax^2+bx+c=0
plug in your variables
a=1 b=6 c=25
So...
and...
and...
The negative number beneith the radical will result in an imaginary expression.
Thus...
So...
or...
Remember, first factor out the 2 in the numerator and then cancel...
and...
So the solution set is...
{-3+4i,-3-4i}
So for the equation...
2x^2-9x=1
Use the same process first making equation equal to zero.
So...
2x^2-9x=1 (subtract 1 from both sides of the equation then begin)
2x^2-9x-1=0
Again x^2 indicates 2 solutions
Use quadratic formula by plugging in indicated variables
a=2 b=-9 c=-1 (remember -b means the OPPOSITE of the value of b)
So...
Then...
And...
89 is aprime number so there is no square root.
So you final result is the solution set... ,
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