SOLUTION: Here's a tough-ey... Imaginary Numbers: 2i+3/4-i + 1-i/4+i Any Help Is GREATLY Appreciated. Thank You In Advance.

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Here's a tough-ey... Imaginary Numbers: 2i+3/4-i + 1-i/4+i Any Help Is GREATLY Appreciated. Thank You In Advance.      Log On


   

Question 37560: Here's a tough-ey... Imaginary Numbers:
2i+3/4-i + 1-i/4+i
Any Help Is GREATLY Appreciated.
Thank You In Advance.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2i+3/4-i + 1-i/4+i
One fraction at a time:
1st:
(2i+3)/(4-i)
Multiply numerator and denominator by (4+i) to get:
[(2i+3)(4+i)]/[16+1]=[12-2+11i]/17=[10+11i]/17
2nd:
Multiply num and denom by 4-1 to get:
[(1-i)(4-i)]/17= [(4-1)-5i]/17=[3-5i]/17
Adding 1st and 2nd you get:
[13+6i]/17
Cheers,
Stan H.