SOLUTION: 2. A random sample of 10 children at a particular elementary school had their hearing tested and received the following scores. 51, 50, 49, 43, 56, 46, 45, 32, 52, 58. If the aver

Algebra ->  Probability-and-statistics -> SOLUTION: 2. A random sample of 10 children at a particular elementary school had their hearing tested and received the following scores. 51, 50, 49, 43, 56, 46, 45, 32, 52, 58. If the aver      Log On


   

Question 375516: 2. A random sample of 10 children at a particular elementary school had their hearing tested and received the following scores. 51, 50, 49, 43, 56, 46, 45, 32, 52, 58. If the average score for normal hearing youngsters is 52, is there reason to believe that on the average, children at this school do not have normal hearing?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

*Note: Formula for the test statistic is t+=+%28x+-+mu%29%2F%28sigma%2Fsqrt%28n%29%29

In this case n = 10

Entering the Data into an Excel worksheet column and applying the Data Analysis tool

found mu+=+48.2 and sigma+=+7.36 for this sampling.

t+=+%2848.2+-52%29%2F%287.36%2Fsqrt%2810%29%29 = -3.8/2.328 = -1.632

P(t < -1.632) can be found using the NORMSDIST(-1.632)function in Excel

or by looking at an usual standard normal table.

P(t < -1.632) = .05134 or 5.1%

The test results show that this sampling is in the low range of normal hearing