SOLUTION: Solve {{{ ln(x-6)+ln(x+3)=ln22 }}}

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Question 375445: Solve
+ln%28x-6%29%2Bln%28x%2B3%29=ln22+
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Solving

+ln%28x-6%29%2Bln%28x%2B3%29=ln22+

+ln%28x-6%29%2Bln%28x%2B3%29-ln22=0+

+ln%28%28x-6%29%28x%2B3%29%2F22%29=0+



10^0 = [(x-6)(x+3)]/22

1 = [(x-6)(x+3)]/22

22 = (x-6)(x+3)

22 = x^2 -3x - 18

0 = x^2 -3x - 40

factoring

(x-8)(x+5)= 0

(x+5) = 0

x = -5  extraneous solution

(x-8)=0

x = 8