SOLUTION: what is the standard form, radius, and center of this circle equation: x^2+y^2-2x+6y-15=0

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Question 374781: what is the standard form, radius, and center of this circle equation: x^2+y^2-2x+6y-15=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y.
x%5E2-2x%2By%5E2%2B6y-15=0
%28x%5E2-2x%2B1%29%2B%28y%5E2%2B6y%2B9%29-15=1%2B9
%28x-1%29%5E2%2B%28y%2B3%29%5E2=10%2B15
highlight%28%28x-1%29%5E2%2B%28y%2B3%29%5E2=25%29
.
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(h,k)=(1,-3)
R=5