SOLUTION: Find the inverse of the logarithmic function f(x)=-ln(x-2).
Steps I've done so far:
1. f(x)=-ln(x-2)
2. y=-ln(x-2)
3. x=-ln(y-2)
What is the next step? I am not sure what
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Find the inverse of the logarithmic function f(x)=-ln(x-2).
Steps I've done so far:
1. f(x)=-ln(x-2)
2. y=-ln(x-2)
3. x=-ln(y-2)
What is the next step? I am not sure what
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Question 374584: Find the inverse of the logarithmic function f(x)=-ln(x-2).
Steps I've done so far:
1. f(x)=-ln(x-2)
2. y=-ln(x-2)
3. x=-ln(y-2)
What is the next step? I am not sure what to do with -ln.
My instructor said the answer is: y=e^-x+2 but I don't know how he gets the -x. I know ln also stands for e.
y=-e^x+2 makes more sense to me. Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! After x = -ln(y-2):
-x = ln(y - 2). Then raise e to both these powers, , , . This is the inverse function.
