SOLUTION: In an equilateral triangle, if the lengths of the three sides are 5x − 2, 6x − 10, and 4x + c, what are the values of x and c?
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Question 374219: In an equilateral triangle, if the lengths of the three sides are 5x − 2, 6x − 10, and 4x + c, what are the values of x and c? Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! 5x- 2 = 6x-10 = 4x+c.
Equate the 1st and the 2nd expressions: 5x - 2 = 6x-10, or -2 + 10 = 6x-5x, or x = 8. Equate the 2nd and the 3rd expressions : 6x-10 = 4x+c, or 2x - 10= c, or c = 2*8-10 = 16-10 = 6.
Therefore x = 8, and c = 6.
