SOLUTION: i)- Solve the following equations for 0° < x < 360°. a) 2sinx cosx = 3 sinx b) 1 - cosx = &#8730;3

Algebra ->  Trigonometry-basics -> SOLUTION: i)- Solve the following equations for 0° < x < 360°. a) 2sinx cosx = 3 sinx b) 1 - cosx = &#8730;3      Log On


   

Question 374128: i)- Solve the following equations for 0° < x < 360°.
a) 2sinx cosx = 3 sinx
b) 1 - cosx = √3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
a) +++2sin%28x%29%2Acos%28x%29+=+3%2Asin%28x%29
2cos%28x%29=3
cos%28x%29=3%2F2
No solution.
.
..
b) +++1+-+cos%28x%29+=sqrt%283%29
cos%28x%29=1-sqrt%283%29
cos%28x%29=-0.7321
highlight%28x=137.1%29degrees and highlight%28222.9%29degrees