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Question 374097: Find two integers whose product is 104 such that one of the integers is three less than twice the other integer.
Answer by rfadrogane(214)   (Show Source):
You can put this solution on YOUR website! Find two integers whose product is 104 such that one of the integers is three less than twice the other integer.
Sol'n:
Let x = the 1st integer
y = the 2nd integer
xy = 104 ----(1)
x = 2y - 3 ----(2)
substitute (2)into (1)
y(2y-3)=104
2y^2 - 3y - 104 = 0, factor
(y-8)(2y+13)= 0
y = 8 & -6.5
from (1)
x = 104/y, subs. the value of y to find the value of x.
let y = 8,
x = 104/8 = 13
let y = -6.5
x = 104/(-6.5) = -16
and finally:
when x = 13, y = 8 -----answer
and, when x = -16, y = -6.5 -----answer
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