SOLUTION: Subtract (4a^3+6a^2-5) from the sum of (a^3-4a+3) and (3a-6a^3+2)

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Question 373963: Subtract (4a^3+6a^2-5) from the sum of (a^3-4a+3) and (3a-6a^3+2)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First calculate the sum,
S=%28a%5E3-4a%2B3%29%2B+%283a-6a%5E3%2B2%29
S=%28a%5E3-6a%5E3%29%2B%28-4a%2B3a%29%2B%283%2B2%29
S=+-5a%5E3-a%2B5
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.
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%28-5a%5E3-a%2B5%29-%284a%5E3%2B6a%5E2-5%29+=-5a%5E3-a%2B5-%284a%5E3%2B6a%5E2-5%29

%28-5a%5E3-a%2B5%29-%284a%5E3%2B6a%5E2-5%29+=highlight%28-5a%5E3-6a%5E2-a%2B10%29