SOLUTION: Can you please help me. Solve 1+2sinθ= cscθ for θ in an interval ( 0º less than or equal to θ less than or equal to 360º) Thank you very much!

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Question 373949: Can you please help me.
Solve 1+2sinθ= cscθ for θ in an interval ( 0º less than or equal to θ less than or equal to 360º)
Thank you very much!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1%2B2sin%28theta%29=1%2Fsin%28theta%29
sin%28theta%29%2B2%28sin%28theta%29%29%5E2=1
Let u=sin%28theta%29
2u%5E2%2Bu-1=0
%282u-1%29%28u%2B1%29=0
Two solutions:
2u-1=0
2u=1
u=1%2F2
sin%28theta%29=1%2F2
highlight%28theta=30%29º and highlight%28theta=150%29º
.
.
.
u%2B1=0
u=-1
sin%28theta%29=-1
highlight%28theta=270%29º