SOLUTION: Find three consecutive odd integers such that the sum of all three is 36 less than the product of the smaller two.

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Question 373702: Find three consecutive odd integers such that the sum of all three is 36 less than the product of the smaller two.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
x + x+2 + x+4 = x(x+2)-36,
3x+%2B+6+=+x%5E2+%2B+2x++-36,
0+=+x%5E2+-x++-42,
0 = (x - 7)(x + 6), or x = 7. (Eliminate x = -6)
Therefore the three consecutive odd integers are 7,9,11.