SOLUTION: the perimeter of a rectangle is twice the sum of its width and it length. the perimeter is 40meters and its lenght is 2 meters more than twice its width.

Algebra ->  Linear-equations -> SOLUTION: the perimeter of a rectangle is twice the sum of its width and it length. the perimeter is 40meters and its lenght is 2 meters more than twice its width.      Log On


   

Question 373243: the perimeter of a rectangle is twice the sum of its width and it length. the perimeter is 40meters and its lenght is 2 meters more than twice its width.
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
p=2%28W%2BL%29
P=40
L=2%2BW


40=2%28W%2B%282%2BW%29%29 divide by 2
20=2W%2B2 subtract 2
18=2W divide by 2
9=W


L=2%2BW substitute W for 9
L=11