SOLUTION: please help me with the substitution method. 3(y-1)=2(x-3) 3y-2x=-3 ----------- y=3x y=3x+1 ----------- -

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Question 37302This question is from textbook Elementary and intermediate Algebra
: please help me with the substitution method.
3(y-1)=2(x-3)
3y-2x=-3
------------
y=3x
y=3x+1
-------------
 This question is from textbook Elementary and intermediate Algebra

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
3(Y-1)=2(X-3) OR 3Y=2X-6 OR Y=(2X-6)/2 SUB (2X-6)/2 FOR Y IN EQUATION #2 WE GET
3(2X-6)/2-2X=-3 OR (6X-18)/2-2X=-3 OR 3X-9-2X=-3 OR X=6 THWN Y=(2*6-6)/2 OR
Y=(12-6)/2 OR Y=6/2 OR Y=3
Y=3X SUB IN EQUATION #2 WE GET 3X=3X+1 3X-3X=1 0=1 NO SOLUTIONS