SOLUTION: What are the intercepts for the equation: y=x^2-4x+4

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Question 372725: What are the intercepts for the equation: y=x^2-4x+4
Found 3 solutions by Fombitz, checkley79, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
y=x%5E2-4x%2B4
y=%28x-2%29%5E2
.
.
To find the x-intercept, set y=0 and solve for x.
y=%28x-2%29%5E2
y=%28x-2%29%5E2=0
x-2=0
x=2
(2,0)
.
.
.
To find the y-intercept, set x=0 and solve for y.
y=%28x-2%29%5E2
y=%280-2%29%5E2
y=4
(0,4)
.
.
.

Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2-4x+4
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2+-4x+%2B4%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, x^2 -4x +4).
Intercepts(0,4)(2,0)
Proof using the (2,0) x & y values:
0=2^2-4*2+4
0=4-8+4
0=0

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

intercepts for the equation:

y = x^2-4x+4  y-intercept (0,4)  (y is 4 when x = 0)

0 = x^2-4x+4

factoring

(x-2)(x-2) = 0

(x-2)= 0

(x-2) =0 

x = 2

x - Intercept (2,0)