SOLUTION: 12. Write an equation in slope-intercept form of the line through point P(–10, 1) with slope –5. (1 point) (A)y = –5x – 49 (B)y – 1 = –5(x + 10) (C)y – 10 = –5(x + 1) (D)y

Algebra ->  Triangles -> SOLUTION: 12. Write an equation in slope-intercept form of the line through point P(–10, 1) with slope –5. (1 point) (A)y = –5x – 49 (B)y – 1 = –5(x + 10) (C)y – 10 = –5(x + 1) (D)y      Log On


   

Question 372687: 12. Write an equation in slope-intercept form of the line through point P(–10, 1) with slope –5. (1 point)
(A)y = –5x – 49
(B)y – 1 = –5(x + 10)
(C)y – 10 = –5(x + 1)
(D)y = –5x + 1
Found 2 solutions by ewatrrr, Alan3354:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Write an equation in slope-intercept form

line through point P(–10, 1) with slope –5

the standard point-slope form for an equation of a line y = mx + b  

where m is the slope and b the y-intercept.

y = -5x + b  Using ordered pair Pt(-10,1) to solve for b

1 = -5*-10 + b

-49 = b

y = -5x -49

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
B & C are not in slope-intercept form.
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Sub -10 for x and see if y = 1 in A and D
A: y = -5*(-10) - 49
y = 50 - 49 = 1
A works.
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D: y = -5x + 1 = -5*(-10) + 1
y = 51 not even close
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A is it.