SOLUTION: What is the solution for this equation? 2x^2=3x-2? I first moved the 2x over then set it to = 0, but i'm not sure if that is the correct way to solve. I factored then and got

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: What is the solution for this equation? 2x^2=3x-2? I first moved the 2x over then set it to = 0, but i'm not sure if that is the correct way to solve. I factored then and got      Log On


   



Question 372657: What is the solution for this equation?
2x^2=3x-2?
I first moved the 2x over then set it to = 0, but i'm not sure if that is the correct way to solve. I factored then and got 2x(x-2)-1(x-2)=0, which i then put as (2x-2)(x-2). I got the answers x=2, x=1/2. I'm confused because I am not sure if this was the way to solve, or if I should have used the quadratic formula?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2=3x-2
2x%5E2-3x%2B2=0
You made a mistake on the next step.
2x%28x-2%29-1%28x-2%29=0
Because if I work it forward,
2x%5E2-4x-x%2B2=0
2x%5E2-5x%2B2=0
I don't end up with the original equation.
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2x%5E2-3x%2B2=0
Yes, you should have used the quadratic formula,
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%283+%2B-+sqrt%28+%283%29%5E2-4%2A2%2A2+%29%29%2F%282%2A2%29+
x+=+%283+%2B-+sqrt%28+9-16+%29%29%2F%284%29+
x+=+%283+%2B-+sqrt%28+-7%29%29%2F%284%29+
highlight%28x+=+%283+%2B-+sqrt%28+7%29i%29%2F%284%29%29+where i=sqrt%28-1%29