SOLUTION: Find two consecutive odd integers such that twice the larger is 17 more than the smaller.

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Question 372518: Find two consecutive odd integers such that twice the larger is 17 more than the smaller.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let the odd integers be x & x+2
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twice the larger = 2(x+2)
17 more than the smaller
= x+17
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2(x+2) = x+17
2x+4 =x+17
2x-x= 17-4
x= 13
13, 15 are the integers
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m.ananth@hotmail.ca