SOLUTION: I having trouble getting this radical expression to solve. I do not have the root symbol so I will use the forward slash. I get different answers each time I try to solve. Can you
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Question 372500: I having trouble getting this radical expression to solve. I do not have the root symbol so I will use the forward slash. I get different answers each time I try to solve. Can you please help me understand this problem?
/10 − 2x − /5x + 16 = 3
/10-2x=3-/5x+16
(/10-2x)^2= (3- /5x+16)^2
10-2x=9-6/5x+16 + (5x+16)
10=9-6/5x+16
1=6/5x+16
0.1666=/5x+16
0.1666^2=(/5x+16)^2
0.03=5x+256
-255.973 or -256=x Found 2 solutions by Fombitz, ankor@dixie-net.com:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! You can just use sqrt(10-2x) to denote the square root function.
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Square both sides.
Square both sides again,
Two solutions:
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Verify the solutions,
Since would lead to a negative argument for the square root function, it is not a solution.
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You can put this solution on YOUR website! You seem to have the right idea, will go thru it step by step: = 3
: = + 3; I think you have the wrong sign here
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Square both sides, FOIL the right side
10 - 2x = (5x+16) + + 9
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10 - 2x = 5x + 25 +
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10 - 25 - 2x - 5x =
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-7x - 15 =
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square again, FOIL the left side
49x^2 + 105x + 105x + 225 = 36(5x + 16)
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49x^2 + 210x + 225 = 180x + 576
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Combine on the right
49x^2 + 210x - 180x + 225 - 576 = 0
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A quadratic equation
49x^2 + 30x - 351 = 0
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Use the quadratic formula to find x. a=49; b=30; c=-351
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two solutions
x =
x = +2.387755
and
x =
x = -3
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I checked both these solutions in the original problem. You can confirm this yourself, however.
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I'm not surprised that you had difficulty, a dozen ways to go wrong here.