SOLUTION: Using algebra, find three consecutive odd integers, such that the sum of the smallest and twice the second is twenty more than the third.
This is what I have:
20(x + 2(x+2))=
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: Using algebra, find three consecutive odd integers, such that the sum of the smallest and twice the second is twenty more than the third.
This is what I have:
20(x + 2(x+2))=
Log On
Question 372497: Using algebra, find three consecutive odd integers, such that the sum of the smallest and twice the second is twenty more than the third.
This is what I have:
20(x + 2(x+2))= x+6 Answer by Fombitz(32388) (Show Source):
