Question 37227: The sum of two consectutive positive integers is 11 less than their product.
find the integers.
Answer by jcmtnez(53)   (Show Source):
You can put this solution on YOUR website! Let call those integers x and y, if they are consecutives y=x+1.
x+(x+1)=x(x+1)-11 The sum of two consectutive positive integers is 11 less than their product.
2x+1=x^2+x-11
0=x^2-x-12
Using the general formula for solving quadratic equations we get x1=4,x2=-3
Then if the integers are positive they are 4 and 5, 4+5=9, 4*5=20, 20-9=11,
And if they are negative they are -3 and -2, -3+(-2)=-5, -3*(-2)=6, 6-(-5)=11.
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