SOLUTION: I am graphing parabolas. f(x)=-x^2+4x-3 I know that the vertex is (2,1) and that the parabola opens downward. How do I determine the x intercepts and y intercepts. Everyth

Algebra ->  Graphs -> SOLUTION: I am graphing parabolas. f(x)=-x^2+4x-3 I know that the vertex is (2,1) and that the parabola opens downward. How do I determine the x intercepts and y intercepts. Everyth      Log On


   

Question 371918: I am graphing parabolas.
f(x)=-x^2+4x-3
I know that the vertex is (2,1) and that the parabola opens downward.
How do I determine the x intercepts and y intercepts. Everything I keep getting seems to be incorrect.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You can convert to vertex form.
y=-%28x-2%29%5E2%2B1
For y-intercept, set x=0, solve for y.
y=-%280-2%29%5E2%2B1
y=-4%2B1
y=-3
(0,-3)
For x-intercept, set y=0, solve for x.
0=-%28x-2%29%5E2%2B1
%28x-2%29%5E2=1
x-2=0+%2B-+1
x=2+%2B-+1
x=3 and x=1
(3,0) and (1,0)
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