SOLUTION: diana purchased 6 pounds of strawberry and 4 pounds of apples fir $18.90 Then she realized that this was not enough and purchased 3 more pounds of each fruit for $10.17 what was th
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Question 371789: diana purchased 6 pounds of strawberry and 4 pounds of apples fir $18.90 Then she realized that this was not enough and purchased 3 more pounds of each fruit for $10.17 what was the cost per pound for each type of fruit. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! diana purchased 6 pounds of strawberry and 4 pounds of apples fir $18.90 Then she realized that this was not enough and purchased 3 more pounds of each fruit for $10.17 what was the cost per pound for each type of fruit.
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6 pounds of strawberry x pounds
4 pounds of apples for y pounds
$18.90
6x+4y= 18.90..........................1
3 more pounds of each fruit
$10.17
3x+3y= 10.17..........................2
multiply by -2
-6x-6y=-20.34
add this equation to (1)
-6x+6x-6y+4y=-20.34+18.90
-2y=-1.44
/-2
y= -1.44/-2
y = $0.72 per pound of apples
..
plug value of y in equation 2
3x+3y=10.17
3x+3*0.72=10.17
3x+2.16=10.17
-2.16 -2.16
3x=10.17-2.16
3x=8.06
/3
x=$2.68 per pound of strawberry
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m.ananth@hotmail.ca
