SOLUTION: I'm trying to find the area of a triangle. The equation of course would be A=1/2bh. The height is (5 radical 27) and the base is (3 radical 48). So the equation would be 1/2(3 radi

Algebra ->  Test -> SOLUTION: I'm trying to find the area of a triangle. The equation of course would be A=1/2bh. The height is (5 radical 27) and the base is (3 radical 48). So the equation would be 1/2(3 radi      Log On


   

Question 371656: I'm trying to find the area of a triangle. The equation of course would be A=1/2bh. The height is (5 radical 27) and the base is (3 radical 48). So the equation would be 1/2(3 radical 48)(5 radical 27). Can you solve this for me please?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
I continue from where you are stuck
%28%281%2F2%29%2A%283%2A+sqrt%2848%29%29%2A%285%2A+sqrt%2827%29%29%29.
= %28%281%2F2%29%2A%283%2Asqrt%28%282%5E4%29%2A3%29%29%2A%285%2Asqrt%283%5E3%29%29%29
=%28%281%2F2%29%2A+%284%2A3%2Asqrt%283%29%29%2A%283%2A5%2Asqrt%283%29%29%29
=%281%2F2%29%2A%2812sqrt%283%29%29%2A%2815%2Asqrt%283%29%29
=90%2A%28sqrt%283%29%29%5E2
=90*3
=270