SOLUTION: An automobile travels 10km at a speed of 100kph, 40km at 80kph and a 3rd diatance at 50kph. If the average velocity for the trip is 70kph, what is the length of the 3rd distance tr
Algebra ->
Average
-> SOLUTION: An automobile travels 10km at a speed of 100kph, 40km at 80kph and a 3rd diatance at 50kph. If the average velocity for the trip is 70kph, what is the length of the 3rd distance tr
Log On
Question 37161: An automobile travels 10km at a speed of 100kph, 40km at 80kph and a 3rd diatance at 50kph. If the average velocity for the trip is 70kph, what is the length of the 3rd distance travelled? Answer by jcmtnez(53) (Show Source):
You can put this solution on YOUR website! Translating this to an equation you get:
1/10+1/2+d/50=70
Solving the equation we get:
5+25+d=70
d=70-30
d=40 It is the 3rd distance travelled
(